Question

Given: Ray BD bisects prove: <1 and <3 are supplementary

Answer 1

Let's begin by listing out the information given to us:

`\begin{gathered} |BD|\text{ bisects }|EBC|\text{ into equal parts}\Rightarrow\angle1=\angle2 \\ \angle2\text{ is supplementary with }\angle3;\angle2+\angle3=180^(\circ) \\ \therefore\angle1+\angle3=180^(\circ) \end{gathered}`