We have to separate the numbers into groups
2, 9, 8
14, 14, 12, 16, 12,11, 13
25, 23, 28, 22, 25, 24, 28, 25, 22
31, 30, 37, 32, 31, 35, 38
40, 43,
50
75
Now we will arrange each group from smallest to greatest
2, 8, 9
11, 12, 12, 13, 14, 14, 16
22, 22, 23, 24, 25, 25, 25, 28, 28
30, 31, 31, 32, 35, 37, 38
40, 43
50
75
Now we will take the ten-digit as stem and the unit-digit as leaf
a)
Stem----Leaf
0. 2, 8, 9
1 1, 2, 2, 3, 4, 4, 6
2. 2, 2, 3, 4, 5, 5, 5, 8, 8
3. 0, 1, 1, 2, 5, 7, 8
4. 0, 3
5. 0
6
7. 5
b)
The median is the middle number
Since we have 30 numbers, then
The median will be the average of the 15th and 16th numbers
Let us find them
The 15th is 25
The 16th is 25
Then the median = (25 + 25)/2 = 50/2 = 25
Median = 25
To find the first quartile we will find the medina of the first 15 numbers
The middle number of 15 numbers is the number in the 8th position
The first 15 numbers are
2, 8, 9, 11, 12, 12, 13, 14, 14, 16, 22, 22, 23, 24, 25
The number in the 8th position is 14
The 1 st quartile is 14
To find the 3rd quartile we will find the median of the last 15 numbers
The last 15 numbers are
25, 25, 28, 28, 30, 31, 31, 32, 35, 37, 38, 40, 43, 50, 75
The median will be the number in the 8th position
The number in the 8th position is 32
The 3rd quartile is 32
The answers are
Median = 25
Q1 = 14
Q3 = 32
C)
To find the interquartile range IQR subtract Q1 from Q3
IQR = 32 - 14 = 18
The answer is
IQR = 18