Question

If velocity of the car is given as v(t)= 10+3t+512. Determine the acceleration at t=2s.

Answer 1

Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

`\begin{gathered} a(t)=(d)/(dt)(v(t)) \\ =(d)/(dt)(10+3t+512) \\ =3m/s^2 \end{gathered}`

Thus, the acceleration of the car at t = 2 s is 3 m/s^2