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If 100g of water at 20 Celsius absorbs 5 kj of heat, by what amount will the temperature of water increase? How do I go about solving this?

User Karunakar
by
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1 Answer

25 votes
25 votes

Answer:

11.96 degrees

Explanations

The formula for finding the heat absorbed by the water is expressed as;


Q=mc\triangle t

where:

• m is the ,mass, of the substance

,

• c is the ,specific heat ,capacity

,

• △t is the ,change in temperature

Given the following parameters

mass = 100g = 0.1kg

c = 4182 J/kg°C

Q = 5kJ = 5000Joules

Required

Change in temperature

Substitute the given parameters into the formula


\begin{gathered} 5000=0.1*4182*(t_f-20) \\ 50,000=4182(t_f-20) \\ (50000)/(4182)=t_f-20 \\ 11.96=t_f-20=\triangle t \\ \triangle t\approx11.96^0 \end{gathered}

This shows that the temperature of the water will increase by 11.96 degrees

User Mdrichardson
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3.2k points