Question

you are standing on the 320 m tall Eiffel tower and throw an egg horizontally how long does it take to hit the ground

Answer 1

Given data:

* The height of the Eiffel tower is 320 m.

* The acceleration due to gravity is,

`g=9.8ms^(-2)`

* The initial velocity of the egg in the vertical direction is 0 m/s.

Solution:

By the kinematics equation, the vertical motion of the egg is,

`H=ut+(1)/(2)gt^2`

where u is the initial velocity, t is the time taken, and H is the height of the egg,

Substituting the known values

`\begin{gathered} 320=0+(1)/(2)*9.8* t^2 \\ 320=4.9* t^2 \\ t^2=(320)/(4.9) \\ t^2=65.306 \\ t=8.08\text{ s} \end{gathered}`

Thus, the time