Question

I put that but I got it wrong I need help

Answer 1

Given:

The height of the recatngle is,

`h=3b^2`

The width of the rectnagle is,

`w=4b^4+2b-6`

Now, the area of the rectangle can be calculated as,

`\begin{gathered} A=wh \\ =(4b^4+2b-6)(3b^2) \\ =4b^4*3b^2+2b*3b^2-6*3b^2 \\ =12b^(4+2)+6b^(1+2)-18b^2 \\ =12b^6+6b^3-18b^2 \end{gathered}`

So, the polynomial representing the area of the rectangle is,

`12b^6+6b^3-18b^2`