Question

A boat can travel 10 miles against a current in the same time that it can travel 40 miles with the current period the right of the current is 3 mph. Find the right of the boat in Stillwater

Answer 1

5 mph

Explanation:

Let the rate (speed) of the boat in still water = x

The speed of the current = 3 mph

Thus:

• The speed against the current = (x-3) mph

,

• The speed with the current = (x+3) mph

`\begin{gathered} Speed=(Distance)/(Time) \\ TS=D \\ \implies Time=(Distance)/(Speed) \end{gathered}`

Since the time it took on both trips is the same, we have that:

`(10)/(x-3)=(40)/(x+3)`

So, we solve the equation for x:

The rate of the boat in still water is 5 mph.