Question

What is the derivative?

Answer 1

`y=(8x^4)/(\ln x)`

By the quotient rule, the derivative is


`(\mathrm dy)/(\mathrm dx)=(\ln x(\mathrm d)/(\mathrm dx)[8x^4]-8x^4(\mathrm d)/(\mathrm dx)[\ln x])/((\ln x)^2)`

`y'=\frac{48x^3\ln x-\frac{8x^4}x}{\ln^2x}`

`y'=(48x^3\ln x-8x^3)/(\ln^2x)`

`y'=(8x^3(6\ln x-1))/(\ln^2x)`