Question

The volume of a gas is 480 mL at 45.0 oC the temperature is increased to 60.0 oC at a constant pressure what is the new volume

Answer 1

The new volume = 0.503 L or 503 mL

Step-by-step explanation

Given:

Initial volume, V₁ = 480 mL = (480/1000) = 0.480 L

Initial temperature, T₁ = 45.0°C = (45 + 273 K) = 318 K

Final temperature, T₂ = 60.0°C = (60 + 273 K) = 333 K

What to find:

The new volume, V₂ when the temperature increases to 60.0°C.

Step-by-step solution:

Since the pressure is constant, the new volume, V₂ can be calculated using Charle's law formula.

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ \\ \Rightarrow V_2=(V_1T_2)/(T_1) \end{gathered}`

Plugging the values of the given parameters into the formula, we have

`V_2=(0.480L*333K)/(318K)=0.503\text{ }L`

The new volume, V₂ when the temperature increased to 60.0°C = 0.503 L or (0.503 x 1000 mL) = 503 mL