80.4k views
0 votes
A bob of mass of 0.18 kilograms is released from a height of 45 meters above the ground level. What is the value of the kinetic energy gained by the bob at the ground level?

250 joules

51 joules

79 joules

8.1 joules

User Vkinra
by
5.3k points

2 Answers

1 vote

Answer:

c:79 joules

Step-by-step explanation:

I took the test on PLATO and it was correct

User StPiere
by
5.6k points
1 vote

Answer: 79 J

Step-by-step explanation:

The value of the kinetic energy at the bottom would be equal to the value of potential energy at the top. This comes from the conservation of energy. At the top, the bob of mass just has potential energy due to its position. At the bottom, potential energy converts entirely to kinetic energy due to its motion.

It is given that mass of the bob is, m = 0.18 kg

height from which it is dropped is, h = 45 m

acceleration due to gravity, g = 9.8 m/s²

Thus, K.E. = P.E. = m g h = 0.18 kg× 45 m × 9.8 m/s² = 79 J

User Ryan Quinn
by
5.8k points