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The half-life of a radioactive kind of copper is 3 hours. if you start with 2,352 grams of it, how much will be left after 9 hours??

User JacobE
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1 Answer

11 votes
11 votes

Answer:

294 grams

Step-by-step explanation:

The amount of radioactive material left after t hours given that the half-life is to hours is


A=P(0.5)^{(t)/(t_0)}

Now, in our case t0 = 3, t = 9 and P = 2352 g; therefore, the above equation gives


A=2352(0.5)^(9/3)
A=294g

which is our answer!

Hence, the amount of radioactive copper left after 9 hours is 294 grams.

User TrialNerror
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