Question

1.The water in the plumbing in a house is at a gauge pressure of 74,000 Pa. What force does this cause on the top of the tank inside a water heater if the area of the top is 0.38 m2?

Answer 1

Given:

The pressure inside the tank, P=74000 Pa

The area of the top of the tank, A=0.38 m²

To find:

The force exerted on the top of the tank.

Step-by-step explanation:

The pressure can be described as the force exerted per unit area.

Thus the pressure inside the tank is given by,

`P=(F)/(A)`

Where F is the force exerted on the top of the tank.

On substituting the known values,

`\begin{gathered} 74000=(F)/(0.38) \\ \implies F=74000*0.38 \\ =28120\text{ N} \end{gathered}`

Final answer:

Thus the force exerted on the top of the tank is 28120 N