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In humans the gene for brown eyes (B) is dominant to the gene for blue eyes and the gene for right handedness (R) is dominant to the gene for left handedness. Two individuals heterozygous for both of these characteristics marry. A) complete a punnett square to show the expected genotypes and phenotypes of the offspring. B) Summarize the ratio of the phenotypes.

User Dectarin
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Final answer:

The punnett square shows that the possible genotypes of offspring are BR, bR, Br, and br, with corresponding phenotypes of brown eyes and right handedness, brown eyes and left handedness, blue eyes and right handedness, and blue eyes and left handedness. The ratio of the phenotypes is 1:1:1:1.

Step-by-step explanation:

To complete a punnett square for this scenario, we need to determine the genotypes of the parents and the possible genotypes and phenotypes of their offspring. Let's assume that B represents the gene for brown eyes and b represents the gene for blue eyes, and R represents the gene for right handedness and r represents the gene for left handedness.

The genotypes of the parents are BbRr, which means they are heterozygous for both characteristics. When we cross these parents, we can create a punnett square by filling in the possible combinations of their alleles:

BbRBRbRrBrbr

The punnett square shows that there are four possible genotypes of offspring: BR, bR, Br, and br. The corresponding phenotypes are brown eyes and right handedness, brown eyes and left handedness, blue eyes and right handedness, and blue eyes and left handedness.

Therefore, the ratio of the phenotypes is 1 brown eyes and right handedness : 1 brown eyes and left handedness : 1 blue eyes and right handedness : 1 blue eyes and left handedness.

User Olegtaranenko
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A. complete a punnet square to show these characteristics but i could me wrong
User Krzysztof Madej
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