39.3k views
9 votes
How do I find out the exact solutions and approximate solutions?

How do I find out the exact solutions and approximate solutions?-example-1

1 Answer

10 votes

Answer: Exact solutions are x = 2√2 and x = -2√2

Approximate solutions are x = 2.828 and x = - 2.828

The attachment shows a portion of the graph with this equation. The "zeros" are the solutions.

Step-by-step explanation: To get values for x, we need to isolate x

2x² -6 = 10 Add 6 to both sides and rewrite the equation as

2x² = 16 divide both sides by 2

x² = 8 Factor 8 as 4(2) so you can "pull out" a square.

To solve for x, take the square roots of both sides.

Remember that square roots are positive and negative values.


√(x^2) = ±
√(4(2))

x = ± 2√2

x = 2√2 and x = -2√2

We can use a calculator to get approximate values of x.


2√(2) = ±2.828427125

Round that to x = 2.828 or 2.83 AND x = - 2.828 for approximate values.

How do I find out the exact solutions and approximate solutions?-example-1
User MUY Belgium
by
4.9k points