Question

1. What would you do with each problem in order to get it in its simplest properform? Use words to explain the specific details to why you used thatprocess/rule.Number 2 a and b

Answer 1

Given

`-6y^0\text{ and \lparen-6y\rparen}^0`

The solutions can be seen below.

Step-by-step explanation

`\begin{gathered} a)\text{ }-6y^0=-6* y^0=-6*1=-6 \\ b)\text{ }(-6y)^0=1 \end{gathered}`

In "a," only the y-value is raised to the power of 1 hence, the reason why y^0 became 1 which then multiplies -6 to get -6. However, in "b", the entire expression is raised to the power of zero, which will then give 1 as the answer.