B. 9m2 + 6m + 6 = 5 has real roots and imaginary roots

Pixelmike asked Dec 7, 2023

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Pixelmike asked Dec 7, 2023

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22 votes

the given equation is

$\begin{gathered} 9m^2+6m+6=5 \\ 9m^2+6m+1=0 \end{gathered}$

we will calculate

$\begin{gathered} =6^2-4*9*1 \\ =36-36 \\ =0 \end{gathered}$

as D is 0 so it has one real root

Jim Counts answered Dec 11, 2023

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