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what is the solution to the system 3x-y+5=02x+3y-4=0A. X= -1, Y= -2B. X= -1, Y= 2C. X= 2, Y= -1D. X= 2, Y= 1

what is the solution to the system 3x-y+5=02x+3y-4=0A. X= -1, Y= -2B. X= -1, Y= 2C-example-1
User Pratik Kamani
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1 Answer

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To find the solution to the system of equation

we will use the elimination method

3x - y = - 5 ----------------------------(1)

2x + 3y = 4 -------------------------------(2)

We will eliminate y and solve for x

multiply equation (1) through by 3

9x - 3y = - 15 ------------------------------------(3)

add equation (2) and equation (3)

11x = -11

divide both-side of the equation by 11

x = -1

substitute x = -1 in equation (1) and solve for y

3x - y = - 5

3(-1) - y = -5

-3 - y = -5

add 3 to both-side of the equation

- y = -5 +3

-y = -2

multiply through byb -1

y = 2

Hence, the correct option is B

User Npiv
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