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Two remote control cars with masses of 1.13 kilograms and 1.94 kilograms travel toward each other at speeds of 8.50 meters per second and 3.79 meters per second, respectively. The cars collide head-on, and the less massive car recoils with a speed of 2.02 meters per second. What is the total kinetic energy of the two cars before the collision? Include units in your answer. Answer must be in 3 significant digits.

User Yakob Abada
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1 Answer

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\begin{gathered} \text{Car 1} \\ \text{mass}=1.13\operatorname{kg} \\ v=8.50\text{ m/s} \\ K=(mv^2)/(2) \\ K=\frac{(1.13\operatorname{kg})(8.50\text{ m/s})^2}{2} \\ K=\frac{(1.13\operatorname{kg})(72.25m^2\text{/s}^2)}{2} \\ K=40.821\text{ J} \\ \text{Car 2} \\ \text{mass}=1.94\operatorname{kg} \\ v=3.79\text{ m/s} \\ K=(mv^2)/(2) \\ K=\frac{(1.94\operatorname{kg})(3.79\text{ m/s})^2}{2} \\ K=\frac{(1.94\operatorname{kg})(14.3641m^2\text{/s}^2)}{2} \\ K=13.933J \\ \text{Total kinetic energy} \\ K_T=40.821J+13.933J \\ K_T=54.754J \\ \text{The total kinetic energy is }54.754J \end{gathered}

User Vladimir Ignatov
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