Answer:
![T=16.58888889hours \approx 16.47hours](https://img.qammunity.org/2022/formulas/mathematics/high-school/db3gbdw7nrzondh313zdemjvt63y9s306q.png)
Explanation:
From the question we are told that
Guy ran 3/4 of Avis's distance
Guy ran 2/4 of Avis's speed
Guy ran
![D=112miles](https://img.qammunity.org/2022/formulas/mathematics/high-school/nctsse944khuirrzpd120vf3kk5y9sckn9.png)
Guy ran at
![6miles/hour](https://img.qammunity.org/2022/formulas/mathematics/high-school/ispfs6ojqo6oq0fqxegdmmpkzc1z40tulu.png)
Let Avis's distance be x
Let Avis's velocity be V'
Generally the Distance and Velocity of Aviv is mathematically Given by
![3/4x=112\\x=149.3333miles](https://img.qammunity.org/2022/formulas/mathematics/high-school/1bxnjjcpuqt7uxwbdhh2zc8oelieaww5ds.png)
and
![2/3V'=6mile/h\\V'=9mile/h](https://img.qammunity.org/2022/formulas/mathematics/high-school/oucym2n2w42eg7d4k5srf22lrmm23qgaok.png)
Generally the time Aviv ran is mathematically Given by
![T=(149.3miles)/(9mile/h)](https://img.qammunity.org/2022/formulas/mathematics/high-school/ql268wwfkju71p10f5iq742ltwhl4z107r.png)
![T=16.58888889hours \approx 16.47hours](https://img.qammunity.org/2022/formulas/mathematics/high-school/db3gbdw7nrzondh313zdemjvt63y9s306q.png)