Question

F(x)=x^2=10x+35 what is the value of h when the function is converted to vertex form

Answer 1

I hope this helps you




y=x^2-10x+35



y=x^2-10x+25+10


y-10=(x-5)^2


y=(x-5)^2+10


h= -(-5)=5


k =10

Answer 2

vertex form is
f (x) = a(x - h)2 + k, where (h, k) is the vertex of the parabola

f(x)=x^2+10x+35

x^2+10x+25-25+35
x^2+5x+5x+25+10
x(x+5)5(x+5)+10
(x+5)^2+10
where h=-5