Question

A new statue in a local park has a length (L), width (W), and height (H) (all in feet) that can be expressed by a system of equations. L+W=28L+H=26W+H=22What is the width of the statue?

Answer 1

To determine the width of the statue:

`\begin{gathered} L+W=28\ldots\ldots..(1) \\ L+H=26\ldots\ldots\ldots(11) \\ W+H=22\ldots\ldots..(111) \end{gathered}`

A local park has a length (L), width (W), and height (H) (all in feet)

Solve equation 1 and 2 simultaneously,

`\begin{gathered} L+W=28 \\ L+H=26 \\ \text{Subtract equation (1) - (11)} \\ W-H=2\ldots\ldots\ldots(IV) \end{gathered}`

Solve equation 3 & 4 simultaneously, make W the subject of formular

`\begin{gathered} W+H=22 \\ W-H=2 \\ \text{Add the two equation} \\ 2W=24 \\ \text{divide both side by 2} \\ (2W)/(2)=(24)/(2) \\ W=12 \end{gathered}`

Therefore the value of width of the statue = 12 feet