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Find f(3) and f'(3), assuming that the tangent line to y=f(x) at a=3 has the equation y=5x+2

1 Answer

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y=5x+2=5x-15+15+2=5(x-3)+17\implies y-17=5(x-3)

The tangent line to
f(x) at
x=c, given the slope
f'(c) at
x=c, is


y-f(c)=f'(c)(x-c)

In this case,
c=3. Matching this with the equation above, you find that
f(c)=17 and
f'(c)=5.
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