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I tried doing it but the whole thing is confusing

I tried doing it but the whole thing is confusing-example-1
User Karstux
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1 Answer

20 votes
20 votes

Given the equation:

y = 828000 - 2700x

Where y is the value of the building and x is the number of months of use.

Let's find when the value of the building will be $666,000.

To find when the value will be $666,000, substitute 666000 for y in the equation and solve for x.

y = 828000 - 2700x

666000 = 828000 - 2700x

Subtract 828000 from both sides:

666000 - 828000 = 828000 - 828000 - 2700x

-162000 = -2700x

Divide both sided by -2700:


\begin{gathered} (-162000)/(-2700)=(-2700x)/(-2700) \\ \\ 60=x \\ \\ x=60 \end{gathered}

The value of the building will be $666,000 after 60 months.

Now, let's convert from months to years.

Where:

12 months = 1 year


60\text{ months = }(60)/(12)=5\text{ years}

Therefore, the value of the building will be $666,000 after 5 years.

ANSWER:

5 years.

User Janek Bogucki
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3.0k points