Question

What is the mass in grams of 9.66x10^24 molecules of methanol

Answer 1

Data:
Molar Mass of CH3OH = 32.04 g/mol

`9.66*10^(24)\:molecules\:of\:methanol=96.6*10^(23)\:molecules\:of\:methanol`

Solving: According to the Law Avogradro, we have in 1 mole of a substance, 6.02x10²³ atoms/mol or molecules

1 mol -------------------- 6.02*10²³ molecules
y mol -------------------- 96.6*10²³ molecules

6.02*10²³y = 96.6*10²³

`y = (96.6*\diagup\!\!\!\!\!\!10^(\diagup\!\!\!\!\!\!23))/(6.02*\diagup\!\!\!\!\!\!10^(\diagup\!\!\!\!\!\!23))`

`\boxed{y \approx 16.04\:mol}`


Solving: Find the mass value now

32.04 g ----------------- 1 mol of CH3OH
x g ------------- 16.04 mol of CH3OH


`x = 32.04*16.04`

`\boxed{\boxed{x = 513.92\:g}}\end{array}}\qquad\quad\checkmark`

Answer:
The mass is 513.92 grams