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How many grams of Tin (SN) would be required to use 6.9 moles of chlorine (cl2)
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How many grams of Tin (SN) would be required to use 6.9 moles of chlorine (cl2)

User Benoit Guigal
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1 Answer

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Sn + Cl₂ → SnCl₂

mole ratio of Cl₂ : Sn is 1 : 1
∴ if moles of Cl₂ = 6.9 mol
then moles of Sn = 6.9 mol

Mass = moles × molar mass

= 6.9 mol × 119 g/mol

= 821.1 g



User Belldandu
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