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Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?
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16 votes
16 votes
Jason is pulling a box across the roompulling with a force of 16 newtons and his arm is making a 68 anglet with the horizontal what is the horizontal component of the he is pulling with?

Jason is pulling a box across the roompulling with a force of 16 newtons and his arm-example-1
User Iamkdblue
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1 Answer

12 votes
12 votes

The horizontal component of a force is defined as follows


F_x=F\cdot\cos \theta

Where F = 16 N, and theta = 68. Let's use these values to find the horizontal component of F.


F_x=16N\cdot\cos 68\approx6N

Therefore, the horizontal component of the pulling force is 6 Newtons.

User Mark Silverberg
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2.8k points
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