Question

What is the equation of the graphed line written in standard form?

x – 4y = 4
x + 4y = 4
y = x – 1
y = –x – 1

Answer 1

First of all, standard form means it should be this form ax+by=c
The equation for the line is
y= 1/4x-1========>Multiply each term by 4
y (4) = 1/4(4)x-1(4)
4y = 4/4x-4
4y=x-4=========>Subtract x from both sides
4y-x=x-x-4

4y-x=-4 OR X-4Y=4
Your answer is A.

Answer 2

we know that

The equation of the line in standard form is equal to

`Ax+By=C`

where

A is a positive integer

B and C are integers

Step 1

Find the slope of the graphed line

we have

`A(0,-1)\ B(4,0)`

The slope of the line is equal to

`m=(y2-y1)/(x2-x1)`

Substitute the values

`m=(0+1)/(4-0)`

`m=(1)/(4)`

Step 2

Find the equation of the line in slope-intercept form

the equation of the line in slope-intercept form is equal to

`y=mx+b`

where

m is the slope

b is the value of the y-intercept

In this problem we have

`m=(1)/(4)`

`b=-1` ------> see the graph

substitute

`y=(1)/(4)x-1`

Step 3

Convert to standard form

Multiply by
`4` both sides

`4y=x-4`

`x-4y=4`

therefore

the answer is the option

`x-4y=4`