Question

The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Which of the following equations is used in the process of solving this problem?

x^2- 7x + 70 = 0
x^2- 7x + 10 = 0
x^2 + 7x - 10 = 0

Answer 1

translating the question
x^2=10-7x
rearrange
x^2+7x-10=0
using quadratic formula
x=-7+ \sqrt{49+40}all over 2 0r x=-7- \sqrt{49+40}all over 2
therefore x=1.2 or x=-1.2

Answer 2

x^2- 7x + 10 = 0 2 possible soultions are 5 or 2