Question

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box.

in.³

Answer 1

170in is the correct answer :)

Answer 2

Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure?

Use 3.14 to approximate π .

Enter your answer in the box. in.³

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting:
`\pi \approx 3.14`

V (volume) = ?

Solving: (Cylinder volume)

`V = \pi *r^2*h`

`V = 3.14 *2.5^2*7`

`V = 3.14*6.25*7`

`V = 137.375 \to \boxed{V_(cylinder) \approx 137.38\:in^3}`

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting:
`\pi \approx 3.14`

If: We know that the volume of a sphere is
`V = 4* \pi * (r^3)/(3)` , but we have a hemisphere, so the formula will be half the volume of the hemisphere
`V = (1)/(2)* 4* \pi * (r^3)/(3) \to \boxed{V = 2* \pi * (r^3)/(3)}`

Formula: (Volume of the hemisphere)

`V = 2* \pi * (r^3)/(3)`

Solving:

`V = 2* \pi * (r^3)/(3)`

`V = 2*3.14 * (2.5^3)/(3)`

`V = 2*3.14 * (15.625)/(3)`

`V = (98.125)/(3)`

`\boxed{ V_(hemisphere) \approx 32.70\:in^3}`

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³

`Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark`

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I Hope this helps, greetings ... Dexteright02! =)