Question

Given the slope of a line is -2 and it passes through the point (4,-5), write the equationof the line in standard form.

Answer 1

2x + y = 3

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

here m = - 2 , then

y = - 2x + c ← is the partial equation

to find c substitute (4, - 5 ) into the partial equation

- 5 = - 8 + c ⇒ c = - 5 + 8 = 3

y = - 2x + 3 ← in slope- intercept form

add 2x to both sides

2x + y = 3 ← equation in standard form

Answer 2

The equation of the line is;

`y=-2x+3`

Step-by-step explanation:

Given that

the slope of a line is -2 and it passes through the point (4,-5).

Applying the slope-intercept form of equation;

`y-y_1=m(x-x_1)`

Substituting the values of the slope and coordinates;

`\begin{gathered} y-(-5)=-2(x-4) \\ y+5=-2x+8 \\ y=-2x+8-5 \\ y=-2x+3 \end{gathered}`

Therefore, the equation of the line is;

`y=-2x+3`