Question

Complete the table and use the results to find the indicated limit.

Answer 1

Given the function:

`k(x)=(x^3-x-6)/(x-2)`

when x = 1.9

`k(x)=(1.9^3-1.9-6)/(1.9-2)=(-1.041)/(-0.1)=10.41`

when x = 1.999

`k(x)=(1.999^3-1.999-6)/(1.999-2)=(-0.0109944)/(-0.001)=10.994001`

When x = 2.001

`k(x)=(2.001^3-2.001-6)/(2.001-2)=(0.011006)/(0.001)=11.006`

When x = 2.1

`k(x)=(2.1^3-2.1-6)/(2.1-2)=(1.161)/(0.1)=11.61`

so, the limit of the function k(x) = 11

The answer is option A. 11