Question

Find the equation of the tangent line to the curve y=11xex at the point (0,0). the equation of this tangent line can be written in the form y=mx

b. find m and
b.

Answer 1

`y=11xe^x\implies y'=11e^x(x+1)`

When
`x=0`, the slope of the tangent line is
`11e^0(0+1)=11`. The equation of the tangent line in point-slope form is then


`y-0=11(x-0)\implies y=11x`