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If I have 10.0g of Mg, what is my theoretical yield of MgCl2

User Fcat
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1 Answer

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Step-by-step explanation:

First, let's write the balanced equation of formation of MgCl2 from Mg and Cl2:

Mg + Cl2 → MgCl2

Now let's transform 10.0g of Mg into moles, using the following formula: moles = mass/molar mass

molar mass of Mg = 24.3 g/mol

moles = 10/24.3

moles = 0.412 moles

Now we use the equation ratio between Mg and MgCl2 to find the quantity of MgCl2 in moles.

1 mole of Mg produces 1 mole of MgCl2.

So 0.412 moles of Mg produces 0.412 moles of MgCl2.

Now we transform 0.412 moles of MgCl2 into mass using the following formula: mass = moles x molar mass

Molar mass of MgCl2: 24.3 + (2*35.45) = 95.21 g/mol

Mass = 0.412 * 95.21

Mass = 39.2 g

Answer: The theoretical yield of MgCl2 is 39.2 g.

User JunKim
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