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a rock dropped from a high platform is moving at 24 ms downward when it strikes the ground. Ignore air resistance. How fast was the rock moving when it had fallen only one-fourth of the distance to the ground?

2 Answers

5 votes

Answer:

6 m/s

Step-by-step explanation:

i took the test

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the main formula to find the speed is depending to
x= 1/2 g t²
v can be found by derivative of x
v= dx / dt= 2x(1/2)gt
so v=gt, if the speed is 24 ms, t = 24/9.8=2.4s
for t =2.4s, the distance is x=d= 1/2x 9.8*2.4²=29.38m

the one fourth of the distance is d'=1/4d=29.38/4=7.05
let's find t
7.05=1/2*9.8*t² implies t=1.19s
and v = gt, so v=9.8*1.19=11.75ms

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