50,910 views
37 votes
37 votes
QUESTION IS IN IMAGE!!! DONT NEED TO SHOW WORK JUST NEED ANSWER!!!!!

QUESTION IS IN IMAGE!!! DONT NEED TO SHOW WORK JUST NEED ANSWER!!!!!-example-1
User Harish ST
by
2.7k points

1 Answer

18 votes
18 votes

Since P is the center of the circle, then the segments PS and PQ are both radii of the circle and have the same measure. Then, the triangle PQS is an isosceles triangle, then, the measures of the angles PQS and QSP must be the same.

Since the sum of the internal angles of a triangle must be equal to 180º, then:


\begin{gathered} m\angle PQS+m\angle QSP+m\angle SPQ=180º \\ \Rightarrow m\angle PQS+m\angle PQS+113º=180º \\ \Rightarrow2m\angle PQS=180º-113º \\ \Rightarrow2m\angle PQS=67º \\ \Rightarrow m\angle PQS=(67º)/(2) \\ \Rightarrow m\angle PQS=33.5º \end{gathered}

The measure of RQS is the same as the measure of PQS.

Therefore, the answer is:


m\angle RQS=33.5º

User Edy Ionescu
by
2.8k points