Question

Can you help to solve for number 5. Solving for X.

Answer 1

We will work at first with the small triangle ADC

`m\angle DAC+m\angle C=m\angle ADB`

mm
`m\angle DAC=55-20=35^(\circ)`We will use the sine rule

`(65)/(\sin35)=(AD)/(\sin 20)`

By using the cross multiplication

`\begin{gathered} AD*\sin 35=65*\sin 20 \\ AD=(65\sin 20)/(\sin 35) \end{gathered}`

In triangle ABD

We will use

`\sin 55=(x)/(AD)`

Then

`x=AD\sin 55`

Substitute AD by its value above