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Changing Volume If each edge of a cube is increasing at the constant rate of 3 centimeters per second, how fast is the volume increasing when x, the length of an edge, is 10 centimeters long?

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Calculus! First one I've seen here! Take the derivative of the volume of a cube. Volume is V = s^3, dV = 3s^2 ds when s = 10 and ds = 3. I think you used x. Anyway, in the derivative fill in the s with a 10 and the ds (rate of change) is 3. So dV = 3(10)^2 * 3
dV = 600 cm per second
User Ajay Jadhav
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