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34 votes
34 votes
Lora (of mass 54 kg) is an expert skier. She

starts at 2.6 m/s at the top of the lynx run,
which is 51 m above the bottom.
What is her final kinetic energy at the bottom of the ski run?

Lora (of mass 54 kg) is an expert skier. She starts at 2.6 m/s at the top of the lynx-example-1
User Pedromateo
by
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1 Answer

14 votes
14 votes

The mechanical energy at top =Mechanical energy at bottom

  • Mass=m=54kg
  • Height=h=51m
  • Acceleration due to gravity=g=10m/s^2
  • Velocity=v=2.6m/s


\\ \tt\longmapsto M_(initial)=M_(Final)

  • Final energy at bottom=The kinetic energy


\\ \tt\longmapsto KE=M_(initial)


\\ \tt\longmapsto KE=P.E_((Top))+K.E_((Top))


\\ \tt\longmapsto K.E=mgh+(1)/(2)mv^2


\\ \tt\longmapsto K.E=m\left(gh+(v^2)/(2)\right)


\\ \tt\longmapsto K.E=54\left((10)(51)+(2.6^2)/(2)\right)


\\ \tt\longmapsto K.E=54\left(510+(6.76)/(2)\right)


\\ \tt\longmapsto K .E=54(510+3.38)


\\ \tt\longmapsto K.E=54(513.38)


\\ \tt\longmapsto K.E=27722.52J


\\ \tt\longmapsto K.E=27.7KJ

User Slmyers
by
2.9k points