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20 points! The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π

20 points! The figure is made up of a cylinder and a hemisphere. To the nearest whole-example-1

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The answer ia 170. I really hope this helps(Either that or 881.3).



User Coffeeyesplease
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Hello!

The figure is made up of a cylinder and a hemisphere. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π

Data: (Cylinder)

h (height) = 7 in

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting:
\pi \approx 3.14

V (volume) = ?

Solving: (Cylinder volume)


V = \pi *r^2*h


V = 3.14 *2.5^2*7


V = 3.14*6.25*7


V = 137.375 \to \boxed{V_(cylinder) \approx 137.38\:in^3}

Note: Now, let's find the volume of a hemisphere.

Data: (hemisphere volume)

V (volume) = ?

r (radius) = 2.5 in (The diameter is 5 being twice the radius)

Adopting:
\pi \approx 3.14

If: We know that the volume of a sphere is
V = 4* \pi * (r^3)/(3) , but we have a hemisphere, so the formula will be half the volume of the hemisphere
V = (1)/(2)* 4* \pi * (r^3)/(3) \to \boxed{V = 2* \pi * (r^3)/(3)}

Formula: (Volume of the hemisphere)


V = 2* \pi * (r^3)/(3)

Solving:


V = 2* \pi * (r^3)/(3)


V = 2*3.14 * (2.5^3)/(3)


V = 2*3.14 * (15.625)/(3)


V = (98.125)/(3)


\boxed{ V_(hemisphere) \approx 32.70\:in^3}

Now, to find the total volume of the figure, add the values: (cylinder volume + hemisphere volume)

Volume of the figure = cylinder volume + hemisphere volume

Volume of the figure = 137.38 in³ + 32.70 in³


Volume\:of\:the\:figure =170.08 \to \boxed{\boxed{\boxed{Volume\:of\:the\:figure = 170\:in^3}}}\end{array}}\qquad\quad\checkmark

_______________________

I Hope this helps, greetings ... Dexteright02! =)

User Predictor
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