Find the minimum value of the function f(x)=2x2-22x+68 to the nearest hundredth

Machiel Visser asked Apr 15, 2023

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Machiel Visser asked Apr 15, 2023

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6 votes

Minimum value of the function

To calculate the minimum value we will use the derivative.

$\begin{gathered} f^(\prime)(x)=4x-22 \\ 4x-22=0 \\ 4x=22 \\ x=(22)/(4) \\ x=5.5 \end{gathered}$

The answer would be 5.5

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