Question

How you find the limit of (√t + t²)/4t-t² as x approaches positive infinity?

Answer 1

`\displaystyle\lim_(t\to\infty)(\sqrt t+t^2)/(4t-t^2)=\lim_(t\to\infty)\frac{\frac1{t^(3/2)}+1}{\frac4t-1}=\lim_(t\to\infty)\frac1{-1}=-1`

Or, if you actually did mean to find the limit as
`x\to\infty`, then the result would simply be the limand
`(\sqrt t+t^2)/(4t-t^2)`, since this expression doesn't depend on
`x` (as far as can be seen).