Question

The circle below is centered at the point (2,-1 ) and had a radius of length 3 what is its equation

Answer 1

The standard equation for a circle is

`\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ \text{where} \\ a=2 \\ b=-1 \\ r=\text{radius}=3 \\ (x-2)^2+(y-(-1))^2=3^2 \\ (x-2)^2+(y+1)^2=3^2 \\ \end{gathered}`