Question

How many joules of heat are required to heat 125 g aluminum from 19.0°C to 95.5°C?

Answer 1

The specific heat of aluminum is 0.902 J/gC. E=m*cp*delta T, or
125*0.902*(95.5-19)= 8630 J

Answer 2

Answer: The amount of heat required is 8625.4 J

Step-by-step explanation:

To calculate the heat required, we use the equation:

`q=mc\Delta T`

where,

q = heat required = ?

m = mass of aluminium = 125 g

c = specific heat capacity of aluminium = 0.902 J/g.°C

`\Delta T` = change in temperature =
`T_2-T_1=95.5-19=76.5^oC`

Putting values in above equation, we get:

`q=125g* 0.902J/g.^oC* 76.5^oC\\\\\q=8625.4J`

Hence, the amount of heat required is 8625.4 J