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The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions?

Which of the following equations is used in the process of solving this problem?

a. x^2 - 7x + 70 = 0
b. x^2 - 7x + 10 = 0
c. x^2 + 7x - 10 = 0

2 Answers

3 votes
The answer is possibly B
User Jcreason
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3 votes
x^2=-10+7x
x^2-7x+10=0

B is answer
User Feifei
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5.6k points