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Let r and s be the roots of x^2 - 6x + 2 = 0. Find (r - s)^2.

1 Answer

2 votes

Answer:
(r-s)^(2) = 28

Explanation:


  • x^(2) -6x+9=-2+9

  • (x-3)^(2)=7

  • (x-3)= -√(7) or
    √(7) <-- there's no plus/minus sign.

  • (x-3) = -√(7)

  • x = 3 -√(7) <-- root.

  • (x-3) = √(7)

  • x = 3+√(7) <-- root.

  • [(3-√(7))-(3+√(7))]^(2)

  • (3-√(7) -3 - √(7))^(2) <-- don't forget to distribute the negative.

  • (-2√(7))^(2)

  • (4)(7)

  • 28
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