Question

The period T(In seconds) of a pendulum is given by T=2PI(Square root of L/32) Where L stands for length (in feet) of the pendulum If pi =3.14 and the period is 6.28 what is the length

Answer 1

Let me check your question

`T\text{ = 2}\cdot\text{ 3.14}\cdot\text{ }\sqrt[]{L/\text{ 32}}`

`\frac{T}{2\cdot\text{ 3.14}}\text{ = }\sqrt[]{L/\text{ 32}}`

T= the period = 6.28

`(6.28)/(6.28)\text{ = }\sqrt[]{L/\text{ 32}}`

`L/32=1^2`

`L=32`

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Answer

L= 32