Question

The figure is made up of a cone and a cylinder. To the nearest whole number, what is the approximate volume of this figure? Use 3.14 to approximate π . Enter your answer in the box.

Answer 1

38 m³

Step-by-step explanation

To solve this we are going to find the volumes of the cylinder and the cone separately, and then we are going to add them.

Volume of the cylinder:

`V=\pi r^2h`

where

`V` is the volume of the cylinder

`r` is the radius

`h` is the height

We can infer from the picture that the radius of the cylinder is 3 mm and its height is 2 mm, so let's replace the values

`V=(3.14) (2mm)^2(2mm)`

`V=(3.14)(4mm^2)(2mm)`

`V=25.12mm^3`

Volume of the cone:

`V=\pi r^2(h)/(3)`

where

`V` is the volume of the cone

`r` is the radius

`h` is the height

We can infer from our picture that the radius of the cone is 4 mm and its height is 3 mm, so let's replace the values

`V=(3.14)(2mm)^2((3mm)/(3) )`

`V=(3.14)(4mm^2)(1m)`

`V=12.56mm^3`

Volume of the figure = area of the cylinder + area of the cone

Volume of the figure =
`25.12mm^3+12.56mm^3=37.68m^3`

rounded to nearest integer:

Volume of the figure =
`38m^3`