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Find an equation of the straight line tangent, at the given point, to the level curve of the given function passing through that point. f(x, y) = x^{2}- y^{2} at (2, -1)
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Find an equation of the straight line tangent, at the given point, to the level curve of the given function passing through that point. f(x, y) = x^{2}- y^{2} at (2, -1)
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Sep 15, 2018
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Find an equation of the straight line tangent, at the given point, to the level curve of the given function passing through that point.
f(x, y) = x^{2}- y^{2} at (2, -1)
Mathematics
college
Rohit Dhawan
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Rohit Dhawan
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so we're considering the level curve
The tangent line to this curve at (2, -1) will be the value of
at this point. Differentiating yields
and so the slope of the tangent would be
.
The tangent line then has equation
Jignesh Ansodariya
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Sep 20, 2018
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Jignesh Ansodariya
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