Question

Find the zero of 3[2x-(3x-4)]-6(x-3)

Answer 1

First, simplify the expression:

`\begin{gathered} 3\lbrack2x-(3x-4)\rbrack-6(x-3) \\ =3\lbrack2x-3x+4-6(x-3) \\ =3(2x)+3(-3x)+3(4)-6(x-3) \\ =6x-9x+12-6x+18 \\ =6x-9x-6x+12+18 \\ =-3x-6x+12+18 \\ =-9x+12+18 \\ =-9x+30 \end{gathered}`

Then:

`3\lbrack2x-(3x-4)\rbrack-6(x-3)=-9x+30^{}`

To find the zero of the given expression, find the zero of -9x+30:

`\begin{gathered} -9x+30=0 \\ \Rightarrow-9x=-30 \\ \Rightarrow x=(-30)/(-9) \\ \therefore x=(10)/(3) \end{gathered}`

Therefore, the zero of the given expression is 10/3.