Question

Car 1 leaves point A at 5:30 p.m., driving due south atan average speed of 35 mph. Car 2 leaves point A at6:30 p.m., driving due north at an average speed of 45mph. How far apart will the drivers be at 9:30 p.m.?

Answer 1

Explanation:

• Car 1 leaves point A at 5:30 p.m., driving due south at an average speed of 35 mph.

,

• Car 2 leaves point A at 6:30 p.m., driving due north at an average speed of 45 mph.

At 9:30 pm, the time taken by the cars is:

`\begin{gathered} Car\;1:9:30-5:30=4\text{ hours} \\ Car\;2:9:30-6:30=3\text{ hours} \end{gathered}`

The distance covered by each car is:

`\begin{gathered} Distance=Speed* Time \\ \text{Car 1's distance}=35*4=140\text{ miles} \\ \text{Car 2's distance}=45*3=135\text{ miles} \end{gathered}`

Since car 1 drives due South and Car 2 due North of point A:

Therefore, the distance between the drivers at 9:30 p.m. will be:

`Distance=140+135=275\text{ miles}`

The two drivers are 275 miles apart at 9:30 pm.